Question

21
2n
The number 6-^-1, where n is any positive integer, is always divisible
by :​

Answer 1

Answer:

Yaar samaj ni aaya question

Answer 2

Answer:

Step-by-step explanation:

12 is not correct answer - Try for 26.. 26(26–1)(26+1) is not divisible by 12

(n-1) ,n ,(n+1) being three consecutive integers - One of them is definitely divisible by 2 .why ? because int(3/2) =1 ..Similarly one of them is definitely divisible by 3 ..

So, N= (n-1) n (n+1) is always divisible by 6

Can we conclude something else also?

may be , when ’n’ is odd - (n-1) and (n+1) are two consecutive even numbers. Therefore one must be divisible by 2 while the other by 4

2*3*4 =24

Hope it helps

:)