21.6g of ag coin is dissolved in hno3 .when nacl is added to this solution all ag is prepitated as agcl which is found to be 14.35g then % of ag in coin
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21.6g of ag react with hno3 to form!=agno3
when dissolve in Nacl it form = agcl + Nano3
agcl =ag+ cl-
given agcl precipitate 14.35
in agcl (ag) =(cl)
therefore in ag coin 14.35gpure ag is present
therefore percentage ag in coin =14.35/21.35*100
=67.2%
when dissolve in Nacl it form = agcl + Nano3
agcl =ag+ cl-
given agcl precipitate 14.35
in agcl (ag) =(cl)
therefore in ag coin 14.35gpure ag is present
therefore percentage ag in coin =14.35/21.35*100
=67.2%
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