Question

21.6g of silver coins is dissolved in hno3.when nacl is added to this solution all silver is precipitated as agcl The wieght of agcl is 14.35g then percentage of silver in coin

Answer 1

here is the answer ...

Answer 2

Answer: 49.9 % of silver was present in a silver coin.

Explanation:

$AgNO_3+NaCl\rightarrow AgCl+NaNO_3$

Moles of AgCl = $\frac{\text{mass of AgCl}}{\text{MOlar mass of AgCl}}=\frac{14.35 g}{143.32 g/mol}=0.1001 mol$

in one molecular formula of AgCl there are one Ag atom then in 0.1001 mol of AgCl will contain 0.1001 mole of Ag metal.

Mass of Ag metal = Moles of Ag ×  Molar mass of Ag

=$0.1001 moles\times 107.87 g/mol=10.79 g$

$\%\text{of Ag}=\frac{\text{mass of Ag}}{\text{total mass of silver coin}}\times 100=\frac{10.79 g}{21.6 g}\times 100=49.9\%$

The weight of AgCl is 14.35g then percentage of silver in coin is 49.9 %.