Math, asked by HackerzZ7533, 10 months ago

21(√7+√2) rationalise the denominator of the following

Answers

Answered by Anonymous
11

Answer:

 \frac{21}{ \sqrt{7} +  \sqrt{2}  }

 =  >  \frac{21}{ \sqrt{7} +  \sqrt{2}  }  \times  \frac{ \sqrt{7} -  \sqrt{2}  }{ \sqrt{7} -  \sqrt{2}  }

 =  >  \frac{21 \sqrt{7} -  \sqrt{2}  }{ ({ \sqrt{7}) }^{2}  -  { (\sqrt{2}) }^{2} }

 =  >  \frac{21 \sqrt{5} }{7 - 2}

 =  >  \frac{21 \sqrt{5} }{5}

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