Question

21. A ball is thrown vertically upwards from the top of a tower with a speed of 100 m/s. It strikes the pond near
the base of the tower after 25 second. The height of the tower is
(1) 500 m
(2) 125 m
BY 625 m
(4) 425 m​

Answer 1

Answer:

The height of the tower is 562.5 m

Explanation:

Given that,

Speed u= 100 m/s

Time t = 25 sec

Using equation of motion

S_{y}=u_{y}t-\dfrac{1}{2}gt^2+h_{0}.....(I)

Where, u = velocity

t = time

g = acceleration due to gravity

h = height of tower

Put the value in the equation (I)

0=100\times25-\dfrac{1}{2}\times9.8\times25^2+h_{0}

h_{0}=562.5\ m

Hence, The height of the tower is 562.5 m

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