21) A position dependent force F = 5 – 2x + 3x? Newton acts on a small body of mass 2 kg and displaces it form x = 0 to x = 3m. The work done in Joule is:
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Answer:
Given that,
Force F=7−2x+3x
2
We know that,
F=
dx
dw
dw=Fdx
Now, the work done is
∫dw=
0
∫
5
F⋅dx
∫dw=
0
∫
5
(7−2x+3x
2
)dx
W=[7x−
2
2x
2
+
3
3x
3
]
0
5
W=35−25+125
W=135J
Hence, the work done is 135 J
Explanation:
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