Question

21. Calculate the number of atoms OF carbon and oxygen in 0.44g of CO2​

Answer 1

Given:-

• Mass of Carbon = 12g

• Mass of Oxygen = $\rm{C0_{2}}$ = 16 × 2 = 32g.

• 1 mole of Carbon Dioxide = 44g.

To Find:-

• The Number of atoms of Carbon and Oxygen in 0.44g of Carbon Dioxide.

Formulae used:-

• No of mole = $\sf{\dfrac{given\:mass}{Total\:mass}}$

• No of Molecules =$\sf{\dfrac{given\:mass\times{Avagardo\: Constant}}{Total\:mass}}$

Now,

→ No. of mole in 0.44 g of Carbon Dioxide = $\sf{\dfrac{given\:mass}{Total\:mass}}$

→ $\sf{\dfrac{4.4}{44}}$

→ 0.1 moles.

Now,

→ No. of molecules = No. of Mole × Avagardo Constant

→ No. of molecules = 0.1 × 6.022 × 10²³

→ No. of molecules = 6.022 × 10²²

But, $\rm{C0_{2}}$ Contains 1 atom of Carbon Dioxide and 2 atoms of Oxygen.

So,

→ Number of carbon atoms =$\sf{ 1\times{ 6.022}\times{10^{22}}}$

→ 6.022 × 10²²

→ No of Oxygen atoms = 2 × 6.022 × 10²²

→ 12.044 × 10²²

Hence, The number of atoms of carbon and oxygen is 6.022 × 10²² & 12.044 × 10²² respectively.