Question

21. He years ago a man was seven times as old as his son. Five years hence, the father will be
three times as old as his son. And their present ages. ​

Answer 1

Let Five years ago the age of son be x years and age of father be 7x years

Present age of son =x+5

Present age of father =7x+5

5 years later their age will (x+10) and (7x+10)

∴7x+10=3(x+10)

7x−3x=20

4x=20

x=5

So, the present age of son=x+5=5+5=10years

and the present age of father=7x+5=35+5=40years

Answer 2

her answer is 8 okay you are understand you are better understand