Question

21. How far should a man of mass 60 kg run so that his kinetic energy is 750 J?​

Answer 1

E.K=750 J

Mass=60 kg

E.K=1/2mv^2

750=1/2×60×v^2

750=30×V^2

V^2=750/30

=25

V=5m/s

Answer 2

Answer:

5 metres per second

Explanation:

I am going to assume you meant fast and not far.

K.E. = 1/2 mv^2

v = √[(2 × K.E.) / m]

v = √[(2 × 750) / 60]

v = √25

v = 5 m/s