Question

21. If |Z + 3| = 2 then prove that (x + 3)2 + y2 = 4​

Answer 1

Step-by-step explanation:

$z = \\ 2 - 3 = - 1$

$(x + 3)2 + y2 = 4$

$2x + y2 = 4 - 6$

$2x + y2 = - 2$

$2x +y = - 2 \div 2$

$(2x + 6) + y2 = 4$

$2x + y = - 1$

$x + y = - 1 \div 2$

$x + y = -0.5$ is false