Math, asked by gulamhusain1480, 9 months ago

21 in the adjoining figure, D and E are mid-points of the
sides BC and CA respectively of a AABC, right angled
at Prove that
10 HAD - AAC + BC2
(1) 402-40C2+ AC
(1) 4(ADBE) = 5AB2

Answers

Answered by Itznikhilhere

0

$\longmapsto\tt{here\:is\:your\:answer}$

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