21. In the given figure AB = DC,
AB I AD, DC I BC
Prove: AD = BC.
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Given: In the given figure.
AB=DC,AB∣∣BC
Proof: AB∣∣DC
∠ABD=∠CDB (Alternate angles)
In △ABD and △CDB
AB=DC
∠ABD=∠CDB (Alternate angles)
BD=BD (common)
△ABD≅CDB (SAS axiom)
AD=BC
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