Question

21 litres of water in a tank is to be divided into 3 equal parts using 5, 8, 12 capacity cans the minimum number of transfer needed to achieve this is?

Answer 1

Equal distribution of 21 l of water in 3 parts yields 7 liters per container.

Step-by-step explanation:

1. In step 1, fill the 12 L container with water
2. Transfer some of this water into the 5 L tank such that it fills the container.
3. The remaining amount of water present in the 12 L container amounts to 7 L of water, which is transferred to the 8 L container.
4. The 12 L of tank is again completely filled with water and some of the water is transferred to the 5 L can. The 12 L of can contains 7 L of water.
5. The remaining water in the 5 L of can and 2 L remaining in the primary container amount of 7 L of water.
6. Thus, 21 L of water can be effectively divided into 3 cans containing 7 L of water.

Answer 2

Answer:

Step-by-step explanation:

Solution is explained in the attached image.

Answer is minimun of 7 transfers