211/125,Is the number have terminating decimal expansion and why?
Answers
Answered by
3
Hello,
Answer: Yes,the number have terminating decimal expansion
Solution:
As we know that, rational numbers are those which can be represented in the form of p/q,where q ≠ 0.
The rational numbers those having denominator in the form of
are of terminating decimal expansion. where n,m are positive integers ,can be zero too.
and those don't have denominator in the above said form,are non terminating repeating decimal.
This the number is terminating decimal.
hope it helps you
Answer: Yes,the number have terminating decimal expansion
Solution:
As we know that, rational numbers are those which can be represented in the form of p/q,where q ≠ 0.
The rational numbers those having denominator in the form of
are of terminating decimal expansion. where n,m are positive integers ,can be zero too.
and those don't have denominator in the above said form,are non terminating repeating decimal.
This the number is terminating decimal.
hope it helps you
Answered by
1
Hi ,
******************************************
Let x = p/q be a rational number ,
such that the prime factorisation of
' q ' is of the form 2^n5^m , where
n and m are non - negative integers.
Then , x has a decimal expansion
which terminates .
*********************************************
Here ,
x = 211/125 = p/q
q = 125 = 5³
q is of the form 2^n5^m , where
n = 0 , m = 3 ,
Therefore ,
211/125 is a terminating decimal.
I hope this helps you.
: )
******************************************
Let x = p/q be a rational number ,
such that the prime factorisation of
' q ' is of the form 2^n5^m , where
n and m are non - negative integers.
Then , x has a decimal expansion
which terminates .
*********************************************
Here ,
x = 211/125 = p/q
q = 125 = 5³
q is of the form 2^n5^m , where
n = 0 , m = 3 ,
Therefore ,
211/125 is a terminating decimal.
I hope this helps you.
: )
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