Math, asked by TbiaSupreme, 1 year ago

211/125,Is the number have terminating decimal expansion and why?

Answers

Answered by hukam0685
3
Hello,

Answer: Yes,the number have terminating decimal expansion

Solution:

As we know that, rational numbers are those which can be represented in the form of p/q,where q ≠ 0.

The rational numbers those having denominator in the form of
 {2}^{n}  \times  {5}^{m}
are of terminating decimal expansion. where n,m are positive integers ,can be zero too.

and those don't have denominator in the above said form,are non terminating repeating decimal.

 \frac{211}{125}  \\  \\  =  \frac{211}{ {5}^{3} }  \\  \\  or \:  \\ =  \frac{211}{ {5}^{3}  \times  {2}^{0} }  \\
This the number is terminating decimal.
 \frac{211 \times  {2}^{3} }{ {5}^{3}  \times  {2}^{3} }  \\  \\  =  \frac{1688}{1000}  \\  \\  = 1.688
hope it helps you

Answered by mysticd
1
Hi ,

******************************************
Let x = p/q be a rational number ,

such that the prime factorisation of

' q ' is of the form 2^n5^m , where

n and m are non - negative integers.

Then , x has a decimal expansion

which terminates .

*********************************************

Here ,

x = 211/125 = p/q

q = 125 = 5³

q is of the form 2^n5^m , where

n = 0 , m = 3 ,

Therefore ,

211/125 is a terminating decimal.

I hope this helps you.
: )



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