(216-x3) = (6-x) (x2+ax+b) then a\b=
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216 is 6 cube
and formula for P^3-Q^3 =(P-Q)(P^2+Q^2+PQ)
so if we put P=6 and Q=x , we get
6^3-x^3 = (6-x)(6^2×x^2+6x)
& now compare it with given question
we get
b=6^2=36
a=6
=> a/b =6/36 =1/6
and formula for P^3-Q^3 =(P-Q)(P^2+Q^2+PQ)
so if we put P=6 and Q=x , we get
6^3-x^3 = (6-x)(6^2×x^2+6x)
& now compare it with given question
we get
b=6^2=36
a=6
=> a/b =6/36 =1/6
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