Question

21x³y⁴+35x⁴y³_49x²y⁵ by-7x²y³​

Answer 1

Answer:

A

0

Consider x4−y4

It can be expanded as (x2−y2)(x2+y2)

(∵ a2−b2=(a−b)(a+b))

It can be further expanded as (x−y)(x+y)(x2+y2)

Now,we can observe that x−y is a factor of x4−y4  

Hence, on dividing x4−y4 with x−y  we get a remainder of Zero.