Math, asked by husnain62782, 7 months ago

The roots of the quadratic equation 2x² – 2√2x + 1 = 0 are *

1/√2 , 1/√2

1/√2 , - 1/√2

1/√2 , √2

√2 , √2

Answer The Correct And Please Explain​

Answers

Answered by RvChaudharY50
9

Question :- The roots of the quadratic equation 2x² – 2√2x + 1 = 0 are :-

1/√2 , 1/√2

1/√2 , - 1/√2

1/√2 , √2

√2 , √2

Answer :-

→ 2x² – 2√2x + 1 = 0

Splitting the Middle term we get,

→ 2x² - √2x - √2x + 1 = 0

→ (2x² - √2x) - (√2x - 1) = 0

→ √2x(√2x - 1) - 1(√2x - 1) = 0

Taking common Now,

→ (√2x - 1)(√2x - 1) = 0

Putting Both Equal to zero Now, we get,

→ √2x - 1 = 0

→ √2x = 1

x = (1/√2)

Similarly,

√2x - 1 = 0

→ √2x = 1

→ x = (1/√2)

Hence, Roots of the given quadratic equations are {(1/2) , (1/2)}.

Answered by Anonymous
4

Answer:

option b is correct .

please see the attachment .

Step-by-step explanation:

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