Math, asked by sonalidhiman123, 10 months ago

2x^2+x^2-6x-3 ÷ x^2-3

Answers

Answered by memoonaayyaz

0

Answer:

(3x-3)(x+1)/(x^2-3)

Step-by-step explanation:

2x^2+x^2-6x-3 ÷ x^2-3

3x^2-6x-3/(x^2-3)

3x(x+1)-3(x+1)/(x^2-3)

(3x-3)(x+1)/(x^2-3)

Answered by debriddhi

0

Check the question . OK I definitely think it's wrong

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