21y5 is a multiple of 3 then value of y is=
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Answered by
2
Hello mate !!
The sum of digits of a multiple of 9 must be equal to 9
Therefore 2+1+y+5 = 9
y = 9-2-1-5
y=1
The value of y = 1
Hope it helpful
The sum of digits of a multiple of 9 must be equal to 9
Therefore 2+1+y+5 = 9
y = 9-2-1-5
y=1
The value of y = 1
Hope it helpful
Answered by
2
A number is divisible by 3 if the sum of all digits of the number is divisible by 3.
2+1+y+5 must be divisible by 3.
8+y must be divisible by 3.
So, y can be 1,4,7.
Therefore value of y can be 1, 4 or 7.
Hope it helps uh❤
2+1+y+5 must be divisible by 3.
8+y must be divisible by 3.
So, y can be 1,4,7.
Therefore value of y can be 1, 4 or 7.
Hope it helps uh❤
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