21y5 is a multiple of 3 then value of y is=
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Answered by
4
We know that any multiple of 3 is the sum of itself.
so, 2+1+y+5 = 9
8+y =9
y =9-8
y =1
2+1+y+5 = 12
y+8=12
y=12-8
y=4
Hope it helps you
Answered by
2
Answer:
Step-by-step explanation:
We know that the sum of the digits of the number should be divisible by 3 so that the number is divisible by 3.
Therefore 2+1+y+5 should be divisible by 3.
If y = 1
2+1+(1)+5 = 9 , which is divisible by 3.
If y = 4
2+1+(4)+5 = 12 , which is also divisible by 3.
If y = 7
2+1+(7)+5 = 15 , which is also divisible by 3.
Hence the value of y is either 1 or 4 or 7.
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