Question

22.4
17. The active mass of 20 g of CaCO3 present
in
(A)0.4M
(C) 0.75 M
(B) 0.5 M
(D) 1 M​

Answer 1

Answer:

CaCO3 is a solid and the active mass of pure solids is taken to be 1

so ans is 1 Molar

Answer 2

Explanation:

1. The atomic mass of ca=40 and atomic mass of c=12 and atomic mass of oxygen is 16.
2. so,Ca+C+3O=40+12+16*3(48)=100
3. No. of mole=wt/molecular weight
4. so,20/100=1/5=0.2M