22.4 l of a gas weighs 70 g ar S.T.P. Calculate the weight of the gas if it occupies a volume of 20 litres at 27°C and 700 mm hg of pressure
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1 mol of any gas at STP occupies 22.4 L
Therefore Molar mass of gas 70 g/mol
Now,
n = PV / (RT)
= [700 mmHg × 1 atm/(760 mmHg)] × 20 L / (0.0821 L atm /(mol K) × 300 K)
= 0.75 mol
Mass of gas = 0.75 mol × 70 g/mol
= 52.5 g
Therefore Molar mass of gas 70 g/mol
Now,
n = PV / (RT)
= [700 mmHg × 1 atm/(760 mmHg)] × 20 L / (0.0821 L atm /(mol K) × 300 K)
= 0.75 mol
Mass of gas = 0.75 mol × 70 g/mol
= 52.5 g
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