Question

2²+4², 2³+4³ find hcf​

Answer 1

QUESTION : Find HCF of (2²+4²) & (2³+4³)

METHOD USED :

• Finding HCF by prime factorization
• In this method, 1stly we have to find prime factor of each number
• Thne taking those factors in account which are present in both numbers

Solution :

• firstly simplifying both numbers

2²+4² = (2×2)+(4×4) = 4 + 16 = 20

2³+4³ = (2×2×2) + (4×4×4) = 8 + 64 = 72

• Now find prime factor of both numbers
• 20 = 2×2×5
• 72 = 2×2×2×3×3

as both 20 & 72 have (2×2) as common

Therefore , HCF of 20 & 72 is 4

in other words , HCF of (2²+4²) & (2³+4³) is 4

ANSWER : HCF of (2²+4²) & (2³+4³) = 4

Answer 2

According to question to have to find the HCF of 2²+4², 2³+4³.

Explanation:-

2²+4²

=(2×2)+(4+4)

=4+16

=20

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2³+4³

=(2×2×2)+(4×4×4)

=8+64

=72

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By doing prime factorising of the numbers we will get:-

20=(2×2××5)

72=(2×2×2×3×3)

________________________

Common Factors:-

(2×2)

=4

Hence,HCF of 2²+4², 2³+4³ is 4

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HOPE IT HELPS YOU : )