22.5 litres of gas weighs 70g at S.T.P . calculate the weight of the gas if it occupies a volume of 20litres at 27°C and 700 mm Hg of pressure
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Hi .... friend....here is your answer...
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PV=nRT
R= 0.082
P=700/760= 0.921 atm
T=273+27 = 300
0.921*20 = n *0.082* 300
n= 0.748 moles
1 mole contains 70g
0.748 contains ......?
0.748*70/1 = 52.414
....
.
.
PV=nRT
R= 0.082
P=700/760= 0.921 atm
T=273+27 = 300
0.921*20 = n *0.082* 300
n= 0.748 moles
1 mole contains 70g
0.748 contains ......?
0.748*70/1 = 52.414
pushpendrakumar2:
bro
this question was in my test , which i didn't made
now i know the solution because of you
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