a body has mass 0.5 kg and density 4g/cm3 .calculate the weight of water displaced by it
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Hey.
Here is your answer.
As volume = mass / density
so, volume of the body, v= 0.5kg / 4g/cm^3
so, v = 0.5×1000g / 4g/cm^3 = 125 cm^3
The volume of water displaced is equal to volume of body submerged.
so, volume of water displaced = 125 cm^3
as , density of water = 1 g/cm^3
so, mass of water displaced, m = density × volume of water displaced
so, m = 125 cm^3 × 1 g/cm^3= 125 g
= 0.125 kg
So , weight = m g =0.125×9.81 N
= 1.22625 N
Thanks.
Here is your answer.
As volume = mass / density
so, volume of the body, v= 0.5kg / 4g/cm^3
so, v = 0.5×1000g / 4g/cm^3 = 125 cm^3
The volume of water displaced is equal to volume of body submerged.
so, volume of water displaced = 125 cm^3
as , density of water = 1 g/cm^3
so, mass of water displaced, m = density × volume of water displaced
so, m = 125 cm^3 × 1 g/cm^3= 125 g
= 0.125 kg
So , weight = m g =0.125×9.81 N
= 1.22625 N
Thanks.
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