22 6.022 x 10 Que molecules of a compound 'x' has 10 gm. What is the molarity of Solution containing 5gm of x in 2 litter?
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Answer:
22 6.022 x 10 Que molecules of a compound 'x' has 10 gm. What is the molarity of Solution containing 5gm of x in 2 litter?
Dear student,
Given :-
- molecules of x = 6.022 × 10²²
- mass of x = 10 gm
- volume for molarity, v = 2 L
To find :-
- molarity of solution containing 5 gm of x in 2 litres.
Solution :-
We know by the mole concept that;
nₓ = wₓ/ mwₓ = Nₓ/ Nₐ
where, nₓ = moles of x
wₓ = given weight of x
mwₓ = molecular weight of x
Nₓ = No. of molecules of x
Nₐ = Avagadro Number
Putting the given values in the above formula, we obtain;
wₓ/ mwₓ = Nₓ/ Nₐ
10/ mwₓ = 6.022 × 10²²/ 6.022 × 10²³
10/ mwₓ = 1/ 10
mwₓ = 100 gm
Now, for moles, we know that;
n = wₓ / mwₓ [wₓ for solution]
n = 5/ 100
n = 1/20 moles
For molarity, we know that;
M = n/ volume (L)
Putting the given values in the above formula, we obtain;
M = 1/20 / 2
M = 1/20 × 1/2
M = 1/40
Hence, the molarity of the solution containing 5 gm of x in 2 litres is 1/40.