Question

22. A box contains 3 blue, 2 white and 4 red marbles. If a marble is drawn at random from the box, what is
the probability that it will be.
(i) white?
(ii) blue?
(iii) red?​

Answer 1

✬ White, Blue, Red = 2/9, 1/3, 4/9 ✬

Given:

• A box contains 3 blue , 2 white & 4 red marbles.
• A marble is drawn at random from the box.

To Find:

• Probability of getting each coloured marbles.

Solution: Total number of marbles in the box will be

• Blue + White + Red

• 3 + 2 + 4 = 9

➟ Total outcome = 9

➟ Favourable outcome = 2 white balls

★ Probability = Favourable/Total outcome ★

$\implies{\rm }$ P (White ball) = 2/9

∴ Probability of getting a white ball is 2/9.

___________________

➟ Total outcome = 9

➟ Favourable outcome = 3

$\implies{\rm }$ P (Blue ball) = 3/9 = 1/3

∴ Probability of getting a blue ball is 1/3.

___________________

➟ Total outcome = 9

➟ Favourable outcome = 4

$\implies{\rm }$ P (Red ball) = 4/9

∴ Probability of getting a red ball is 4/9.

Answer 2

Answer:

Given :-

• A box contains 3 blue, 2 white and 4 red marbles. A marble is drawn at random from the box.

To Find :-

• What is the probability of :

1. White marble
2. Blue marble
3. Red marble

Solution :-

First, we have to find the sum of the three marbles,

↪ Blue marble + White marble + Red marble

↪ 3 + 2 + 4

➥ 9

❶ Probability of white marble,

↦ No of white marble = 2

Probability of getting a white marble,

↦ $\dfrac{2}{9}$

➤ Probability of white marble is $\dfrac{2}{9}$

❷ Probability of blue marble,

⇒ No of blue marble = 3

Probability of getting a blue marble,

⇒ $\dfrac{\cancel{3}}{\cancel{9}}$

➠ Probability of blue marble is $\dfrac{1}{3}$

❸ Probability of red marbles,

➞ No of red marbles = 4

Probability of getting red marbles,

➞ $\dfrac{4}{9}$

➽ Probability of red marbles is $\dfrac{4}{9}$

$\therefore$ Probability of white marble is 2/9, blue marble is 1/3 and red marbles is 4/9 .