Question

22. A rectangle has twice the area of a square. The length of the rectangle is 12 cm greater and the
width is 8 cm greater than a side of the square. Find the side of the
square.
(A) 24cm
(B 20 cm
(C) 22 cm
(D) 30 cm​

Answer 1

Answer:

Step-by-step explanation:

Hope it helps

Answer 2

Answer:

24cm

Step-by-step explanation:

let the side of the square be y

length of greater side of the rectangle= y+12

width of the smaller side of the rectangle = y+8

Area of square = y^2

Area of the rectangle = (y+12)(y+8)

= y^2+8y+12y+96

= y^2+20y+96

As per the question : y^2+20y+96= 2y^2

= -y^2+20y+96 = 0

= y^2 - 20y - 96 = 0

= y^2- 24y + 4y -96 = 0

= y(y-24) + 4(y-24)= 0

= y-24=0 ; y+4 = 0

= y=24 ; y= -4

Since -4 is not possible. so y = 24cm

So the option (a) is correct