22) A room is 8m long, 5m broad and 4m high. There are two doors each 3m x 1.2m and two
windows each 1.5m x 1.2m. Find the cost of
(1) distempering the walls at Rs.12.50 per sq.m
(in) carpeting the floor at Rs.50 per m.
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Answered by
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Step-by-step explanation:
L.S.A of room ( Area of four walls) = 2(l+b) × h
= {2(8+5) ×4} m2
= (2 × 13 ×4) m2
= (8 × 13) m2
= 104 m2
Area of two doors = { 2( l × b) } m2
= { 2( 3 × 1.2) } m2
= { 2 × 3.6 } m2
= 7.2 m2
Area of two windows = { 2( l× b) } m2
= { 2( 1.5 × 1.2 ) } m2
= { 2 × 1.8 } m2
= 3.6 m2
Now, Area of walls = L.S.A of room - ( Area of two doors + Area of two windows)
= 104 m2 - ( 7.2+3.6) m2
= 104 m2 - 10.8 m2
= 93.2 m2
(I) Cost of distempering the walls = Rs.(93.2 × 12.50)
= Rs.1165
(ii) 1. If Rs.50 per "m"
Cost of carpeting the floor = Rs.( 8 × 50)
= Rs. 400
2. If Rs.50 per " m2"
Cost of carpeting floor = Rs. ( 40 × 50)
= Rs. 2000
Hope you satisfied with my answer..
ANYWAYS, LET'S STAY AWESOME
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