22. A speeding car changes its velocity from 108 kmh 'to 36 kmh in 4 s. Calculate its deceleration in
(a) ms 2 (b) kmh ?
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a)u=108×5/18=30 m/s
v=36×5/18=10 m/s
t=4 s
a= (v-u)/t
= (10-30)/4
= -20/4
= -5 m/s^2
So , Deceleration = 5m/s^2
b)u=108 km/h
v=36 km/h
t=4 s=4/3600=1/900 h
a= (v-u)/T
= (36-108)/(1/900)
= -72×900
= -64800 km/h^2
So , Deceleration = 64800 km/h^2
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arzoo19:
what is the logic of 5 here
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