Question

22. A tree broke at a height of 2.5 dm from the ground and its top touches the ground at a distance of 6 dm from the base of the tree. Find the original height of the tree.​

Answer 1

Answer:

Original length = 9m

Step-by-step explanation:

Given,

Tree broke at a height of 2.5 dm

It touches the ground at a distance of 6dm from base.

assume it as a right triangle

hypotenuse =

$\sqrt{b ^{2} + h^{2} }$

b= base

h=height

hypotenuse =

$\sqrt{6^{2} + 2.5^{2} }$

hypotenuse=

$\sqrt{42.25}$

hypotenuse= 6.5

tree length = broken length(hypotenuse)+ standing length(2.5dm)

tree length = 6.5 + 2.5

tree length = 9 dm

Original length = 9dm