Question

22. An object, 4.0 cm in size, is placed at 50.0 cm in front of concave mirror of focal length 25.0 cm. Select the row containing the correct position of image and magnification produced: Position of image +50 cm +50 cm -1 (a) (b) (c)-50 cm (d) -25, Magnification -1 -2​

Answer 1

Answer:

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Explanation:

हा क्षण है ऊं ऐं श्रीं 2जी को आग लगाई थी कि इस प्रकार विकसित कर रही सीबीआई निदेशक हैं इस बात कहती थी क्योंकि ये सच कहूं या फिर एक को एक

Answer 2

Explanation:

1) Use formula ,

1/v + 1/u = 1/f

⇒1/v + 1/-25 = 1/-15

⇒1/v = 1/-15 + 1/25 = (-25 + 15)/375 = 1/-37.5 cm

⇒ v = – 37.5 cm

The image is formed object side , 37.5cm from the pole of concave mirror.

(ii) Now, use formula,

H2/H1 = -u/v

Where Hi is the size of the image .

Now, H2/4cm = -(-37.5cm)/(-25cm)

H2= -4 × 37.5/25 cm = -6cm

∴ size of image = 6cm