Math, asked by amoghhosanagar45, 6 hours ago

x ^ { 3 } - 64 y ^ { 3 }

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Answered by prnavya29

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Answered by faleehamanal

x³ - 64y³

= x³ - (4y)³
ID: a³ - b³ = (a - b) [a² + ab + b²]

= (x - 4y) [(x)² + (x)(4y) + (4y)²]
= (x - 4y) (x² + 4xy + 16y²)

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x ^ { 3 } - 64 y ^ { 3 }​

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x ^ { 3 } - 64 y ^ { 3 }