Question

22. Find the percentage increase in the area of a triangle if its each side is doubled?
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Answer 1

Answer:

Semi-perimeter of the triangle, s=2a+b+c

Area of triangle  =s(s−a)(s−b)(s−c).

When each side is doubled, the new sides are 2a,2b,2c. 

Hence, new s′=22a+2b+2c=2(2a+b+c)=2s

New area A′=2s(2s−2a)(2s−2b)(2s−2c)

=2×2×2×2×s(s−a)(s−b)(s−c)

=4s(s−a)(s−b)(s−c).

∴ % change in Area =AA′−A×100

=s(s−a)(s−b)(s−c)4s(s−a)(s−b)(s−c)−s(s−a)(s−b)(s−c)×

Answer 2

Answer:

Solution :

Step-by-step explanation:

Hope this helps you .......