Question

22. Find the roots of the quadratic equation (3x - 2)^2 - 4(3x-2) +3 = 0​

Answer 1

Answer:

Please refer to the picture.

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Answer 2

Answer:

(3x -2)² - 4(3x -2) + 3 = 0

(3x-2)² - 12x +8 + 3 = 0

(3x-2)² - 12x +11 = 0

9x² + 4 - 12x - 12x + 11 = 0

9x² - 24x + 15 = 0

3x² - 8x + 5 = 0

3x² -5x - 3x + 5 = 0

x(3x-5) -1(3x -5) = 0

(3x - 5)(x-1) = 0

x = 1 and x = 5/3

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