Question

22. Find the values of p and q such that the equation
x2 + px +q=0 has 5+3i as a root:​

Answer 1

HI ATHARVA....!!!!

HERE IS YOUR SOLUTION

EXPRESSSION=>X^2+PX+Q=0

ONE ROOT=>5+3I

WE KNOW THAT IF ROOTS ARE IMAGINARY THEN,THEY COME IN PAIRS

SO THE OTHER ROOT WILL BE =>5-3I

SUM OF ROOTS => -B/A

5+3I+5-3I=-P/1

10=-P

-10=P

ALSO,PRODUCT OF ROOTS=C/A

5+3I X 5-3I =Q/1

25- 9I^2=Q

25+9=Q

Q=34 \

I HOPE THIS HELPS PLZ MARKIT AS THE BRAINLIEST....!!