Question

22) For the circuit given below. calculate.
a) current in each resistor
b) total current drawn from the battery
c) equivalent resistance of the circuit​

Answer 1

Answer:

Explanation:

These all resistor are in parallel so

Net resistance= 3ohm

And others answer are in below image

Answer 2

Given,

A circuit is shown in the figure.

To find,

a) current in each resistor

b) total current drawn from the battery

c) equivalent resistance of the circuit

Solution,

We can simply solve this numerical problem by using the following process:

Let us assume that the equivalent resistance of the circuit is R ohms.

Mathematically,

As per ohms law," For a voltage V across the conductor, current I flowing through the conductor and resistance R provided by the conductor to the flow of current, V = RI "

{Statement-1}

If a set of resistors are arranged in a parallel type of arrangement, then the reciprocal of the equivalent resistance of the arrangement is equal to the sum of the reciprocals of the individual resistances.

Also, the voltage across all the resistors arranged parallelly is equal to the voltage supply across the circuit, but the total current gets divided.

{Statement-2}

Now, according to the question;

(1/R) = (1/5 + 1/10 + 1/30)

{using statement-2}

=> (1/R) = (6/30 + 3/30 + 1/30)

=> (1/R) = (10/30) = 1/3

=> R = 3 ohms

Now, according to statement-1, we get;

Total current drawn from the battery

= total current flowing through the circuit

= (voltage supply across the circuit)/(equivalence resistance of the circuit)

= 6V / 3 ohms

= 2 A

Now, according to statement-2, we get;

Current flowing through the 5 ohms resistor

= (voltage supply across the resistor)/(resistance of the resistor)

= 6V / 5 ohms

= 1.2 A

Current flowing through the 10 ohms resistor

= (voltage supply across the resistor)/(resistance of the resistor)

= 6V / 10 ohms

= 0.6 A

Current flowing through the 30 ohms resistor

= (voltage supply across the resistor)/(resistance of the resistor)

= 6V / 30 ohms

= 0.2 A

Hence, the equivalent resistance of the circuit is equal to 3 ohms and the total current drawn from the battery is equal to 2 A. The total current flowing through the 5 ohms resistor is equal to 1.2 A, the current flowing through the 10 ohms resistor is equal to 0.6 A, and the current flowing through the 30 ohms resistor is equal to 0.2 A, respectively.