Physics, asked by harihiran99421, 9 months ago

22. Four organ pipes of equal length have their overtones
as shown. Frequency ratio of sound waves in them is

(1) 4:3:2:1
(2) 6:5:4:3
(3)8:7:6:5
(4) 5:3:2:1​

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Answers

Answered by poojabagai1210
4

Explanation:

2.6:5:4:3

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Answered by minasharmaminaedu
1

Answer:

The answer is option 2) 6:5:4:3

Explanation:

The open end of the tube, where motion is unrestricted, is where the standing wave's max air displacement , while the closed tip, where the air movement is stopped, has no displacement at all. The length of the line is equal to the distance between a node and an antinode, or one among a wavelength, therefore lambda Equals 4L. A disturbance introduced at or close to the tube's closed end can result in the same resonance, as demonstrated in (Figure). Regardless of how it is caused, it is preferable to think of this as a spontaneous vibration of a air column.

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