Question

22. If a + b + c = 0, then the value of
a² + b² + c²/
(bc + ca + ab)
is
(1) 2
(2) -2
(3) 4
(4) 4​

Answer 1

Answer:

-2

Step-by-step explanation:

we know (a+b+c)^2=a^2+b^2+c^2+2(ab+bc+ca)

in the question a+b+c = 0

therefore

0=a^2+b^2+c^2+2(ab+bc+ca)

so

-2(ab+bc+ca)=a^2+b^2+c^2

so

-2=a^2+b^2+c^2/bc+ca+ac

HOPE IT HELPS YOU