22. If the point A (X,2) B(3,4) and C(7,8) are collinear. what is the value of x
plz... answer give the correct answer
Answers
Step-by-step explanation:
Given:-
The points A (X,2) B(3,4) and C(7,8) are collinear.
To find:-
What is the value of x ?
Solution:-
Given points are A (X,2) ,B(3,4) and C(7,8)
(x1, y1)=A (X,2)=>x1 = X and y1 = 2
(x2, y2)=B(3,4)=>x2 = 3 and y2 = 4
(x3, y3)=C(7,8)=>x3 = 7 and y3 = 8
Given that the points are collinear points.
We know that
The area of a triangle formed by the points (x1, y1),(x2, y2) and (x3, y3) is equal to zero then the they are collinear points.
Area of triangle =(1/2)|x1(y2-y3)+x2(y3-y1)+x3(y1-y2)| sq.units
=>∆=0
=>(1/2)|x1(y2-y3)+x2(y3-y1)+x3(y1-y2)| = 0
On Substituting the values in the above formula then
=>(1/2) | X(4-8)+3(8-2)+7(2-4) |= 0
=>(1/2) | X(-4)+3(6)+7(-2) | = 0
=>(1/2) | -4X+18-14 | = 0
=>(1/2) | -4X+4 | = 0
=>(-4X+4 )/2 = 0
=>(-4X+4)=0×2
=>-4X+4 = 0
=>-4X = -4
=>X = -4/-4
=>X = 1
Therefore, X = 1
Answer:-
The value of X for the given problem is 1
Used formulae:-
- The points lie on the same line are called collinear points.
- The area of a triangle formed by the points (x1, y1),(x2, y2) and (x3, y3) is equal to zero then the they are collinear points.
Area of triangle =(1/2)|x1(y2-y3)+x2(y3-y1)+x3(y1-y2)| sq.units
Answer:
Question
❇️If the point A (X,2) B(3,4) and C(7,8) are collinear. what is the value of x
Solution
✍️Refer to the attachment ⬆️
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Extra information
- Answer will always be in positive sign . If it is negative then your answer is wrong
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Extra information
- To find collinear:x1(y2-y3)+x2(y2-y1)+x3(y1-y2)=0
- Distance formula:d(AB)=√(x2-x1)²+(y2-y1)²
- Section formula:
- Midpoint formula:
- centroid formula:
Step-by-step explanation:
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