Question

22. If x'+x- ax + b is divisible by x? - x, then find the value of 'a' and
'b
​

Answer 1

Step-by-step explanation

Here is your answer,

x³ + x² -ax + b is divisible by x² - x or x(x -1) 

 x and (x -1) they are the factors of x³ + x² -ax + b .

.0 and 1 they are the zeros of x³ + x² -ax + b.

PUTTING x = 0

(0)³ + (0)² -a(0) + b = 0 = b = 0

putting x = 1 

(1)³ + (1)² - a(1) + b = 0

1 + 1 - a + b = 0

2 - a + 0 = 0 

a = 2 

HERE IS YOUR ANSWER, a = 2 and b = 0

Hope it helps you!