Question

22. In the adjoining figure, PQ=RS and QR=SP. Find the third pair of
corresponding part and state the property of congruence that makes
∆PQR =∆ PSR.​

Answer 1

answer:

∆PQR=∆PSR by sss rule

Answer 2

Answer:

Given:

PQ=RS and QR=Sap

To do:

We have to find the third pair of corresponding parts that makes trianglePQR ~=triangle PSR

Solution:

In the above figure,

PQ=RS (given)

QR=SP (given)

PR=PR (common side)

Therefore,

trianglePQR~=triangle PSR (By SSS congruency)

The third pair of corresponding parts that makes triangle PQR~= triangle PSR is PR=PR

hope it helps you dear ☺️