Question

using elimination method solve 2y-3÷x=12 and 5y+7÷x=1

Answer 1

Answer:

x= -22/29

y= 157/11

Step-by-step explanation:

There will be two equations :

1) 2y - 3/x = 12

2) 5y + 7/x = 1

Multiplying equation 1) by 5 and 2) by 2,

→ 10y - 30/x = 60

→ 10y + 14/x = 2

- - -. (here we're subtracting the 2 equation)

So, 10y-10y = 0.

-30/x -14/x = -44/x (3)

60-2 = 58 (4)

Now equating (3) and (4),

-44/x = 58

So x = -44/58 = -22/29

Applying x= -22/29 in equation 1),

2y - 3/(-22/29) = 12

→ 2y - (3×29)/-22 = 12

→ 2y + 87/22 = 12

→ 2y = 12 - 87/22 = (244-87)/22 = 157/22

→ y = (157×2)/22 = 314/22 = 157/11

Enjoy :)

[i hope the question wasn't wrong because it does look suspicious. Do meantion in the comment if it was correct or wrong]