Question

22. Prajal tested the solubility of three different substances at different temperatures and collected the data as given below (results are given in the wbie as grams of substance dissolved in 100 gms of water to forma saturated solution​

Answer 1

Question

Pragya tested the solubility of three different substances at different temperatures and collected the data as given below(results are given in the following table, as grams of substance dissolved in 100grams of water to form a saturated solution).

(a) What mass of potassium nitrate would be needed to produce a saturated solution of potassium nitrate in 50grams of water at 313K?

(b) Pragya makes a saturated solution of potassium chloride in water at 353K and leaves the solution to cool at room temperature. What would she observe as the solution cools? Explain.

(c) Find the solubility of each salt at 293K. Which salt has the highest solubility at this temperature?

(d) What is the effect of change of temperature on the solubility of a salt?

Answer:

(a) At 313 K 62 g of potassium nitrate dissolved in 100 g of water. So to produce a saturated solution of potassium nitrate in 50 g of water we need

62/100 ×50=31 g of potassium nitrate.

(b)Some soluble potassium chloride will separate out in the form of crystal at room temperature because the solubility of potassium chloride will decrease.

(c) (i) Solubility of Potassium nitrate at 293 K is 32 g.

(ii) Solubility of sodium chloride at 293 K is 36 g.

(iii) Solubility of Potassium chloride at 293 K is 35g.

(iv) Solubility of Ammonium chloride at 293 K is 37 g.

The solubility of Ammonium chloride is highest at this temperature.

(d)The solubility of salt increases with the increase in temperature.

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Answer 2

Answer:

The whole question is attached.

ANSWER

(a) At 313K,

Mass of potassium nitrate needed to produce a saturated solution of potassium nitrate in 100g are = 62g

Mass of potassium nitrate needed to produce a saturated solution of potassium nitrate in 1g water = 62g/100g

Mass of potassium nitrate needed to produce a saturated solution of potassium nitrate in 1g water = 62gx50g/100g

= 62g/2

=31 g.

(b) Solubility of solids in liquid decreases with decrease in temperature.

Room temperature is 298K while the saturated solution was formed at 253K. Hence, she will find crystals of potassium chloride when the solution cools down.

(c) Solubility is the maximum amount of solute which can be dissolved in 100 gm of Solvent at a particular temperature.

Hence the solubility of the following at 293K is

• Potassium Nitrate - 32.

• Sodium Chloride - 36.

• Potassium Chloride - 35.

• Ammonium Chloride - 37.

(d) From the above table we can see that the solubility of a salt is directly proportional to the temperature.

As the temperature increases the solubility also increases.