Question

22. Show that.
(x+y)(x-y) +(y+z)(y-z) +(z+x)(z-x) =O *​

Answer 1

(x+y)(x-y)+(y+z)(y-z)+(z+x)(z-x)

xsquare-ysquare+ysquare-zsquare+zsquare-xsquare=0

hence proved

Answer 2

Answer:

FIRST WE HAVE TO MULTIPLY (X+1)(X-1) WITH THEOREM OF ALGEBRAIC EXPRESSION

=X^2 -Y^2 +Y^2-Z^2+Z^2-X^2 =

X^2-X^2+Y^2-Y^2+Z^2-Z^2=0

0=0 (PROVED)