Question

22. Sides of a triangle are in the ratio of 12 : 17 : 25 and its perimeter is 540cm. Find its area. ​

Answer 1

Answer:

ratio of sides 12: 17:25

let them be 12x,17x, 25x respectively

perimeter of a triangle = sum of all sides =

540 = 12x,17x, 25x 540 = 54x

x= 10

all sides measure

12x12x10 = 120

17x = 17x 10 = 170 25x= 25 x 10 = 250

it's semiperimeter = 540/2 = 270

using heron's formula area of the triangle =

root {(s)(s-a)(s-b)(s-c)} where s is the semiperimeter and a,b,c

area the sides of the triangle.

root {( 270)(270-120)(270-170)(270-250)}

9000cm^2.

Answer 2

Step-by-step explanation:

ratio of sides

12: 17:25

let them be

12x,17x, 25x respectively

perimeter of a triangle = sum of all sides

540 = 12x,17x, 25x

540 = 54x

x = 10

all sides measure

12x = 12×10 = 120

17x = 17× 10 = 170

25x= 25 × 10 = 250

it's semipetimeter = 540/2

= 270

using heron's formula area of the triangle =

root {(s)(s-a)(s-b)(s-c)}

where s is the semipetimeter and a,b,c

area the sides of the triangle.

root {( 270)(270-120)(270-170)(270-250)}

= 9000cm^2.