Physics, asked by zakas, 10 months ago

22. The electric current in a charging R-C circuit is given
by i = i,
e r where i., R and C are constant
parameters of the circuit and t is time. Find the rate of
change of current at (a) t = 0, (b) t = RC, (c) t = 10 RC.
The electric current in a discharging R-C circuit is given
by i = i, et ke where i,, R and C are constant parameters
and t is time. Let i, = 2:00 A, R=6:00 x 10'12


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Answers

Answered by Anonymous
9

Hope the current equation is i = i* e^(-t/RC)    [since R,C,time parameters are mentioned]

di/dt = i* e^(-t/RC)* -1/RC ....(i)

When , t = 0

di/dt = i * e^0 * -1/RC = -i/RC

When, t= RC

di/dt = i* e^(-RC/RC) * -1/RC = i*e^-1 * -1/RC = - i/eRC

When, t= 10 RC

di/dt = i * e^(-10 RC/RC) * -(1/RC) = i*e^-10 * -1/RC = - i/e^10 * RC

Couldn't figure out the second part.

Answered by deephero
2

Answer:

Explanation:

pl be  my friend help me

Hope the current equation is i = i* e^(-t/RC)    [since R,C,time parameters are mentioned]

di/dt = i* e^(-t/RC)* -1/RC ....(i)

When , t = 0

di/dt = i * e^0 * -1/RC = -i/RC

When, t= RC

di/dt = i* e^(-RC/RC) * -1/RC = i*e^-1 * -1/RC = - i/eRC

When, t= 10 RC

di/dt = i * e^(-10 RC/RC) * -(1/RC) = i*e^-10 * -1/RC = - i/e^10 * RC

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