Question

2216
.) 40 g of Caustic soda (NaOH) contain:
a) 6.022 x 1024molecules of O2
b) 22.4 litres of N2
c) 4 g of Na
d) 6.022 x 1023 atoms of H​

Answer 1

Answer:

40g NaOH ............6.022×10^23 molecules

= 1× 6.022×10^23 atoms of H

Explanation:

so, correct answer is (d)