Question

221x²-392x-2608=0, what is x​

Answer 1

Let's solve your equation step-by-step.

$221x^2-392x-2608=0$

For this equation⇒ $a=221,b=-392,c=-2608$

$221x^{2}+-392x+-2608=0$

Step 1: Use quadratic formula with $a=221,b=-392,c=-2608$.

$x=\frac{-b\pm\sqrt{b^2-4ac} }{2a}$

$x=\frac{-(-392) \pm \sqrt{(-392)^{2}-4(221)(-2608)} }{2(221)}$

$x=\frac{392 \pm \sqrt{2459136} }{442}$

$x=\frac{196}{221}+\frac{8}{221}\sqrt{9606} \ or \ x=\frac{196}{221}+\frac{-8}{221}\sqrt{9606}$

∴ $x=\frac{196}{221}+\frac{8}{221}\sqrt{9606} \ or \ x=\frac{196}{221}+\frac{-8}{221}\sqrt{9606}$ in the equation $221x^2-392x-2608=0$.

Additional Information :)

What is a quadratic equation?

An equation where the highest exponent of the variable is a square is known as quadratic equations.

What is a quadratic formula?

The quadratic formula in maths is ⇒ $x=\frac{-b\pm\sqrt{b^2-4ac} }{2a}$

Basically, a formula that provides the solution to a quadratic equation is known as a quadratic formula.