226x² -241x + 64 = 0. find the roots.
Answers
Answer:
Use the quadratic formula
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x=\frac{-{\color{#e8710a}{b}} \pm \sqrt{{\color{#e8710a}{b}}^{2}-4{\color{#c92786}{a}}{\color{#129eaf}{c}}}}{2{\color{#c92786}{a}}}
x=2a−b±b2−4ac
Once in standard form, identify a, b and c from the original equation and plug them into the quadratic formula.
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226x^{2}-241x+64=0
226x2−241x+64=0
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a={\color{#c92786}{226}}
a=226
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b={\color{#e8710a}{-241}}
b=−241
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6
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c={\color{#129eaf}{64}}
c=64
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x=\frac{-({\color{#e8710a}{-241}}) \pm \sqrt{({\color{#e8710a}{-241}})^{2}-4 \cdot {\color{#c92786}{226}} \cdot {\color{#129eaf}{64}}}}{2 \cdot {\color{#c92786}{226}}}
x=2⋅226−(−241)±(−241)2−4⋅226⋅64
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Answer:
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